WebDec 27, 2016 · $\begingroup$ Do we agree that OP is not in general orthogonal to OQ ? (they are on your figure) $\endgroup$ – Jean Marie. Dec 27, 2016 at 20:33 ... implying $$\dfrac{QX}{OQ}=\dfrac{RO}{YR}~\implies QX\cdot RY = OQ\cdot OR=OQ^2.~\square$$ Share. Cite. Follow edited Feb 1, 2024 at 10:07. Rezwan Arefin. 3,054 1 1 gold badge 11 … WebFrom the equation its been told that the radius of 1st circle is 3cm i.e. OP = OQ = 3cm. Similarly in the second circle, the radius is 4cm. i.e. O ′ = O ′ Q = 4 c m ( O O ′) 2 = ( O P) 2 + ( O ′ P) 3 = 3 2 + 4 2 = 9 + 16 = 25 O O ′ = 25 = 5 c m We have found the length of O O ′ as 5cm. Let us consider the length of OR as x.
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